A simple calculation of fifth grade decimals。
Hi, everyone. I'm sorry for studying. Today we are talking about an improvement on the simple operation of decimal multipliers。
See title: 1. 999 times 370 plus 19. 99 times 6 plus 1999 times 0. 57 equals? After reading the subject, a pattern can be found in which all three multiplication algorithms have the 1999 numbers, but they have different decimal points and different sizes
After reading the title, it turns out that there are multiplications, which all meet the operating requirements of the multiplication method, but they do not have the same numbers, even if they do, but their size and the location of decimal points are different. The same number can be created by magnifying and narrowing。
How many times can these three figures be magnified or reduced into figures, this time into 1999 and 1. 999 into 1999? The 1,000-fold extension became 1999, multiplied by 1999, but would the other multiplier after the 1,000-fold increase also have to be reduced by 1,000 in order to be fair and equitable。
How much does 370 equal to 1,000 times? How many times will it be equal to 0. 37 plus 19. 99 to the 1999 expansion? What is the increase of 100 times to a multiplier of 1999 and 6 times 100 times? 0. 06, it was not expanded in 1999。
What's the total amount? What is the equivalent of the 1999 multiplied by 0. 37 and 0. 06 and 0. 57 and the 1999 multiplied by
How much is 0. 37 plus 0. 57 equal? Seven plus seven equals 14, four plus four plus five equals eight plus one equals nine, a decimal 0. 94 plus 0. 06, 14+6 equals ten, a zero equals one plus nine plus zero = 99 equals ten, and a decimal is one。
If 1999 is not simple by one, it is equal to 1999, so the answer to this topic is 1999。
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